Hey guys, I have been having some trouble with this question related to quadratic formulas. Its a 3 part question, but I only want the first part done, so I can do the rest. Here is the question:3. A rocket is launched vertically from the ground with an initial velocity of 64 . (a) Write a quadratic function h(t) that shows the height, in feet, of the rocket t seconds after it was launched.Thank you so much in advance. I really appreciate it.
Accepted Solution
A:
to find the height that the rocket has reached, we can use the following equation to calculate distance. s = ut + 1/2 at² s - distance - h u - initial velocity - 64 ft/s x 0.3048 m/ft = 19.5 m/s a - acceleration, since the rocket is travelling upwards against gravitational acceleration, its said to be deceleration. therefore value is -9.8 ms⁻² t - time taken - t seconds substituting values in the equation h = 19.5 ms⁻¹ x t s - 1/2 x 9.8 ms⁻² x (t s)² h = 19.5t - 4.9t²